We want to understand why the equation
does not mix independent left-handed and right-handed fields, unlike the Dirac equation.
Define
with
The gamma matrices satisfy
This implies that \(\gamma^\mu\) flips chirality.
Consider
Act with \(\gamma^5\):
So
Therefore \(i\gamma^\mu \partial_\mu \psi_L\) is right-handed.
You are using
A crucial identity is
Now compute
If \(\psi = \psi_L\), then \(\gamma^5 \psi = -\psi\), so
Hence charge conjugation flips chirality: a left-handed field goes to a right-handed charge conjugate.
(a) Dirac equation
Split into chiral parts:
This requires both \(\psi_L\) and \(\psi_R\). A Dirac mass therefore mixes handedness.
(b) Majorana equation
Now start with a left-handed field \(\psi_L\):
The left-hand side, \(i\gamma^\mu \partial_\mu \psi_L\), is right-handed, and the right-hand side, \(m(\psi_L)_c\), is also right-handed.
So the equation matches right-handed to right-handed.
The equation is closed within one chiral sector. You can write the entire dynamics using only \(\psi_L\): the opposite chirality is not an independent field, because it is generated automatically by charge conjugation.
It does not mean chirality never flips. Rather, it means that the theory does not require an independent field of opposite chirality.
Dirac: needs \(\psi_L\) and \(\psi_R\).
Majorana: needs only \(\psi_L\), because the role of the opposite chirality is supplied by \((\psi_L)_c\).
\(\gamma^\mu\) flips chirality, charge conjugation flips chirality, and in the Majorana equation these flips match perfectly. So everything stays self-contained within one Weyl field.
This is why Majorana fermions can be described by a single Weyl spinor, and why the mass term is consistent without introducing new degrees of freedom.
This is additional material to complement page 486 of Group Theory in a Nutshell by Anthony Zee.
Created with assistance from ChatGPT.